m^2=25/49

Solution for m^2=25/49 equation:

m^2=25/49

We move all terms to the left:

m^2-(25/49)=0

We add all the numbers together, and all the variables

m^2-(+25/49)=0

We get rid of parentheses

m^2-25/49=0

We multiply all the terms by the denominator


m^2*49-25=0

Wy multiply elements

49m^2-25=0

a = 49; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·49·(-25)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70}{2*49}=\frac{-70}{98}
=-5/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70}{2*49}=\frac{70}{98}
=5/7
$